At 8 a.m., Wesley left Hotel R in his car and travelled towards Hotel S at 88 km/h. At the same time, Tim left Hotel R in his car and travelled in the opposite direction towards Hotel T. When Tim reached Hotel T at 10.45 a.m., Wesley was 14 km away from Hotel S.
- What was the distance from Hotel R to Hotel S?
- If the distance between Hotel S and Hotel T was 410 km, what was Tim's speed?
(a)
From 8 a.m. to 10.45. am = 2 h 45 min
60 min = 1 h
1 min =
160 h
45 min =
4560 =
34 h
2 h 45 min = 2
34 h
Distance from Hotel R to Hotel S
= 88 x 2
34 + 14
= 88 x
114 + 14
= 242 + 14
= 256 km
(b)
Distance travelled by Tim
= 410 - 256
= 154 km
Tim's speed
= 154 ÷ 2
34 = 154 ÷
114 = 154 x
411 = 56 km/h
Answer(s): (a) 256 km; (b) 56 km/h