At 5 a.m., Perry left Hotel U in his car and travelled towards Hotel V at 76 km/h. At the same time, Caden left Hotel U in his car and travelled in the opposite direction towards Hotel W. When Caden reached Hotel W at 7.30 a.m., Perry was 10 km away from Hotel V.
- What was the distance from Hotel U to Hotel V?
- If the distance between Hotel V and Hotel W was 440 km, what was Caden's speed?
(a)
From 5 a.m. to 7.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel U to Hotel V
= 76 x 2
12 + 10
= 76 x
52 + 10
= 190 + 10
= 200 km
(b)
Distance travelled by Caden
= 440 - 200
= 240 km
Caden's speed
= 240 ÷ 2
12 = 240 ÷
52 = 240 x
25 = 96 km/h
Answer(s): (a) 200 km; (b) 96 km/h