At 6 a.m., Justin left Hotel Y in his car and travelled towards Hotel Z at 80 km/h. At the same time, Fabian left Hotel Y in his car and travelled in the opposite direction towards Hotel A. When Fabian reached Hotel A at 8.30 a.m., Justin was 15 km away from Hotel Z.
- What was the distance from Hotel Y to Hotel Z?
- If the distance between Hotel Z and Hotel A was 430 km, what was Fabian's speed?
(a)
From 6 a.m. to 8.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel Y to Hotel Z
= 80 x 2
12 + 15
= 80 x
52 + 15
= 200 + 15
= 215 km
(b)
Distance travelled by Fabian
= 430 - 215
= 215 km
Fabian's speed
= 215 ÷ 2
12 = 215 ÷
52 = 215 x
25 = 86 km/h
Answer(s): (a) 215 km; (b) 86 km/h