At 6 a.m., Jenson left Hotel W in his car and travelled towards Hotel X at 81 km/h. At the same time, Seth left Hotel W in his car and travelled in the opposite direction towards Hotel Y. When Seth reached Hotel Y at 8.40 a.m., Jenson was 12 km away from Hotel X.
- What was the distance from Hotel W to Hotel X?
- If the distance between Hotel X and Hotel Y was 380 km, what was Seth's speed?
(a)
From 6 a.m. to 8.40. am = 2 h 40 min
60 min = 1 h
1 min =
160 h
40 min =
4060 =
23 h
2 h 40 min = 2
23 h
Distance from Hotel W to Hotel X
= 81 x 2
23 + 12
= 81 x
83 + 12
= 216 + 12
= 228 km
(b)
Distance travelled by Seth
= 380 - 228
= 152 km
Seth's speed
= 152 ÷ 2
23 = 152 ÷
83 = 152 x
38 = 57 km/h
Answer(s): (a) 228 km; (b) 57 km/h