At 9 a.m., Zane left Hotel B in his car and travelled towards Hotel C at 80 km/h. At the same time, Xavier left Hotel B in his car and travelled in the opposite direction towards Hotel D. When Xavier reached Hotel D at 11.30 a.m., Zane was 10 km away from Hotel C.
- What was the distance from Hotel B to Hotel C?
- If the distance between Hotel C and Hotel D was 440 km, what was Xavier's speed?
(a)
From 9 a.m. to 11.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel B to Hotel C
= 80 x 2
12 + 10
= 80 x
52 + 10
= 200 + 10
= 210 km
(b)
Distance travelled by Xavier
= 440 - 210
= 230 km
Xavier's speed
= 230 ÷ 2
12 = 230 ÷
52 = 230 x
25 = 92 km/h
Answer(s): (a) 210 km; (b) 92 km/h