At 6 a.m., Bobby left Hotel C in his car and travelled towards Hotel D at 72 km/h. At the same time, Wesley left Hotel C in his car and travelled in the opposite direction towards Hotel E. When Wesley reached Hotel E at 8.10 a.m., Bobby was 16 km away from Hotel D.
- What was the distance from Hotel C to Hotel D?
- If the distance between Hotel D and Hotel E was 380 km, what was Wesley's speed?
(a)
From 6 a.m. to 8.10. am = 2 h 10 min
60 min = 1 h
1 min =
160 h
10 min =
1060 =
16 h
2 h 10 min = 2
16 h
Distance from Hotel C to Hotel D
= 72 x 2
16 + 16
= 72 x
136 + 16
= 156 + 16
= 172 km
(b)
Distance travelled by Wesley
= 380 - 172
= 208 km
Wesley's speed
= 208 ÷ 2
16 = 208 ÷
136 = 208 x
613 = 96 km/h
Answer(s): (a) 172 km; (b) 96 km/h