At 6 a.m., Ben left Hotel C in his car and travelled towards Hotel D at 80 km/h. At the same time, Ken left Hotel C in his car and travelled in the opposite direction towards Hotel E. When Ken reached Hotel E at 8.30 a.m., Ben was 20 km away from Hotel D.
- What was the distance from Hotel C to Hotel D?
- If the distance between Hotel D and Hotel E was 410 km, what was Ken's speed?
(a)
From 6 a.m. to 8.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel C to Hotel D
= 80 x 2
12 + 20
= 80 x
52 + 20
= 200 + 20
= 220 km
(b)
Distance travelled by Ken
= 410 - 220
= 190 km
Ken's speed
= 190 ÷ 2
12 = 190 ÷
52 = 190 x
25 = 76 km/h
Answer(s): (a) 220 km; (b) 76 km/h