At 5 a.m., Henry left Hotel T in his car and travelled towards Hotel U at 100 km/h. At the same time, Bryan left Hotel T in his car and travelled in the opposite direction towards Hotel V. When Bryan reached Hotel V at 7.15 a.m., Henry was 13 km away from Hotel U.
- What was the distance from Hotel T to Hotel U?
- If the distance between Hotel U and Hotel V was 400 km, what was Bryan's speed?
(a)
From 5 a.m. to 7.15. am = 2 h 15 min
60 min = 1 h
1 min =
160 h
15 min =
1560 =
14 h
2 h 15 min = 2
14 h
Distance from Hotel T to Hotel U
= 100 x 2
14 + 13
= 100 x
94 + 13
= 225 + 13
= 238 km
(b)
Distance travelled by Bryan
= 400 - 238
= 162 km
Bryan's speed
= 162 ÷ 2
14 = 162 ÷
94 = 162 x
49 = 72 km/h
Answer(s): (a) 238 km; (b) 72 km/h