At 6 a.m., Vincent left Hotel C in his car and travelled towards Hotel D at 72 km/h. At the same time, Ken left Hotel C in his car and travelled in the opposite direction towards Hotel E. When Ken reached Hotel E at 8.30 a.m., Vincent was 15 km away from Hotel D.
- What was the distance from Hotel C to Hotel D?
- If the distance between Hotel D and Hotel E was 440 km, what was Ken's speed?
(a)
From 6 a.m. to 8.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel C to Hotel D
= 72 x 2
12 + 15
= 72 x
52 + 15
= 180 + 15
= 195 km
(b)
Distance travelled by Ken
= 440 - 195
= 245 km
Ken's speed
= 245 ÷ 2
12 = 245 ÷
52 = 245 x
25 = 98 km/h
Answer(s): (a) 195 km; (b) 98 km/h