At 5 a.m., Howard left Hotel L in his car and travelled towards Hotel M at 86 km/h. At the same time, Albert left Hotel L in his car and travelled in the opposite direction towards Hotel N. When Albert reached Hotel N at 7.30 a.m., Howard was 15 km away from Hotel M.
- What was the distance from Hotel L to Hotel M?
- If the distance between Hotel M and Hotel N was 390 km, what was Albert's speed?
(a)
From 5 a.m. to 7.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel L to Hotel M
= 86 x 2
12 + 15
= 86 x
52 + 15
= 215 + 15
= 230 km
(b)
Distance travelled by Albert
= 390 - 230
= 160 km
Albert's speed
= 160 ÷ 2
12 = 160 ÷
52 = 160 x
25 = 64 km/h
Answer(s): (a) 230 km; (b) 64 km/h