At 9 a.m., Carl left Hotel D in his car and travelled towards Hotel E at 80 km/h. At the same time, Elijah left Hotel D in his car and travelled in the opposite direction towards Hotel F. When Elijah reached Hotel F at 11.30 a.m., Carl was 15 km away from Hotel E.
- What was the distance from Hotel D to Hotel E?
- If the distance between Hotel E and Hotel F was 430 km, what was Elijah's speed?
(a)
From 9 a.m. to 11.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel D to Hotel E
= 80 x 2
12 + 15
= 80 x
52 + 15
= 200 + 15
= 215 km
(b)
Distance travelled by Elijah
= 430 - 215
= 215 km
Elijah's speed
= 215 ÷ 2
12 = 215 ÷
52 = 215 x
25 = 86 km/h
Answer(s): (a) 215 km; (b) 86 km/h