At 5 a.m., Glen left Hotel X in his car and travelled towards Hotel Y at 70 km/h. At the same time, Peter left Hotel X in his car and travelled in the opposite direction towards Hotel Z. When Peter reached Hotel Z at 7.30 a.m., Glen was 20 km away from Hotel Y.
- What was the distance from Hotel X to Hotel Y?
- If the distance between Hotel Y and Hotel Z was 400 km, what was Peter's speed?
(a)
From 5 a.m. to 7.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel X to Hotel Y
= 70 x 2
12 + 20
= 70 x
52 + 20
= 175 + 20
= 195 km
(b)
Distance travelled by Peter
= 400 - 195
= 205 km
Peter's speed
= 205 ÷ 2
12 = 205 ÷
52 = 205 x
25 = 82 km/h
Answer(s): (a) 195 km; (b) 82 km/h