The distance between City S and City T was 890 km apart. A bus travelled at an average speed of 98 km/h from City S to City T. At the same time, a convertible travelled at an average speed of 80 km/h from City T to City S. How much further did the bus travel than the convertible when the bus met the convertible on the way?
Combined speed of the bus and the convertible
= 98 + 80
= 178 km/h
Time taken for the bus and the convertible to meet
= 890 ÷ 178
= 5 h
Difference in the speed between the bus and the convertible
= 98 - 80
= 18 km/h
Distance that the bus travelled further than the convertible
= 5 x 18
= 90 km
Answer(s): 90 km