The distance between City S and City T was 840 km apart. A car travelled at an average speed of 92 km/h from City S to City T. At the same time, a convertible travelled at an average speed of 76 km/h from City T to City S. How much further did the car travel than the convertible when the car met the convertible on the way?
Combined speed of the car and the convertible
= 92 + 76
= 168 km/h
Time taken for the car and the convertible to meet
= 840 ÷ 168
= 5 h
Difference in the speed between the car and the convertible
= 92 - 76
= 16 km/h
Distance that the car travelled further than the convertible
= 5 x 16
= 80 km
Answer(s): 80 km