The distance between City Z and City A was 910 km apart. A bus travelled at an average speed of 99 km/h from City Z to City A. At the same time, a convertible travelled at an average speed of 83 km/h from City A to City Z. How much further did the bus travel than the convertible when the bus met the convertible on the way?
Combined speed of the bus and the convertible
= 99 + 83
= 182 km/h
Time taken for the bus and the convertible to meet
= 910 ÷ 182
= 5 h
Difference in the speed between the bus and the convertible
= 99 - 83
= 16 km/h
Distance that the bus travelled further than the convertible
= 5 x 16
= 80 km
Answer(s): 80 km