The distance between City U and City V was 920 km apart. A car travelled at an average speed of 95 km/h from City U to City V. At the same time, a convertible travelled at an average speed of 89 km/h from City V to City U. How much further did the car travel than the convertible when the car met the convertible on the way?
Combined speed of the car and the convertible
= 95 + 89
= 184 km/h
Time taken for the car and the convertible to meet
= 920 ÷ 184
= 5 h
Difference in the speed between the car and the convertible
= 95 - 89
= 6 km/h
Distance that the car travelled further than the convertible
= 5 x 6
= 30 km
Answer(s): 30 km