The distance between City K and City L was 890 km apart. A lorry travelled at an average speed of 90 km/h from City K to City L. At the same time, a car travelled at an average speed of 88 km/h from City L to City K. How much further did the lorry travel than the car when the lorry met the car on the way?
Combined speed of the lorry and the car
= 90 + 88
= 178 km/h
Time taken for the lorry and the car to meet
= 890 ÷ 178
= 5 h
Difference in the speed between the lorry and the car
= 90 - 88
= 2 km/h
Distance that the lorry travelled further than the car
= 5 x 2
= 10 km
Answer(s): 10 km