The distance between City A and City B was 890 km apart. A car travelled at an average speed of 100 km/h from City A to City B. At the same time, a convertible travelled at an average speed of 78 km/h from City B to City A. How much further did the car travel than the convertible when the car met the convertible on the way?
Combined speed of the car and the convertible
= 100 + 78
= 178 km/h
Time taken for the car and the convertible to meet
= 890 ÷ 178
= 5 h
Difference in the speed between the car and the convertible
= 100 - 78
= 22 km/h
Distance that the car travelled further than the convertible
= 5 x 22
= 110 km
Answer(s): 110 km