Mrs Long left home at 7 a.m. and drove towards the city. 1¹₄ hour later, Mr Long left the house and drove at an average speed of 95 km/h towards the city. When Mr Long reached his destination at 1 p.m., Mrs Long was 12 km away from the city. Find Mrs Long’s average speed in km/h. Express your answer in mixed number.
1 h = 60 min 
¹₄ h = ¹₄ x 60 = 15 min
1¹₄ = 1 h 15 min

1 h 15 min after 7 a.m. = 8.15 a.m.

Time that Mr Long left the house = 8.15 a.m.

Time that Mr Long took from 8.15 a.m. to 1 p.m. to reach his destination = 4 h 45 min

1 min = ¹₆₀ h
45 min = ⁴⁵₆₀ h = ³₄ h
4 h 45 min = 4³₄ h

Distance that Mr Long drove
= 4³₄ x 95
= 451¹₄ km

Distance that Mrs Long drove when Mr Long reached
= 451¹₄ - 12 
= 439¹₄ km

Time that Mrs Long took to travel from 7 a.m. to 1 p.m. = 6 h

Mrs Long's average speed
= 439¹₄ ÷ 6
= 73⁵₂₄ km/h

Answer(s): 73⁵₂₄ km/h