At 6 a.m., Asher and Henry left Park U and drove towards Park V at average speeds of 90 km/h and 53 km/h respectively. Upon reaching Park V, Asher rested for 3 hours. He then headed back for Park U at an average speed of 90 km/h along the same route. Asher and Henry met each other on their way at 12 noon.
- How far had Asher covered when he met Henry on the way?
- How far apart were the two parks?
(a)
Time taken by Henry = 6 h
Time taken by Asher = 6 - 3 = 3 h
Distance covered by Asher when he met Henry
= 3 x 90
= 270 km
(b)
Distance travelled by Henry
= 6 x 53
= 318 km
Distance of the two parks
= (270 + 318) ÷ 2
= 588 ÷ 2
= 294 km
Answer(s): (a) 270 km; (b) 294 km