At 9 a.m., Albert and Asher left Park S and drove towards Park T at average speeds of 78 km/h and 64 km/h respectively. Upon reaching Park T, Albert rested for 2 hours. He then headed back for Park S at an average speed of 78 km/h along the same route. Albert and Asher met each other on their way at 1 p.m.
- How far had Albert covered when he met Asher on the way?
- How far apart were the two parks?
(a)
Time taken by Asher = 4 h
Time taken by Albert = 4 - 2 = 2 h
Distance covered by Albert when he met Asher
= 2 x 78
= 156 km
(b)
Distance travelled by Asher
= 4 x 64
= 256 km
Distance of the two parks
= (156 + 256) ÷ 2
= 412 ÷ 2
= 206 km
Answer(s): (a) 156 km; (b) 206 km