At 8 a.m., Reggie and Ahmad left Park C and drove towards Park D at average speeds of 90 km/h and 58 km/h respectively. Upon reaching Park D, Reggie rested for 2 hours. He then headed back for Park C at an average speed of 90 km/h along the same route. Reggie and Ahmad met each other on their way at 2 p.m.
- How far had Reggie covered when he met Ahmad on the way?
- How far apart were the two parks?
(a)
Time taken by Ahmad = 6 h
Time taken by Reggie = 6 - 2 = 4 h
Distance covered by Reggie when he met Ahmad
= 4 x 90
= 360 km
(b)
Distance travelled by Ahmad
= 6 x 58
= 348 km
Distance of the two parks
= (360 + 348) ÷ 2
= 708 ÷ 2
= 354 km
Answer(s): (a) 360 km; (b) 354 km