At 6 a.m., Henry and Reggie left Park R and drove towards Park S at average speeds of 72 km/h and 55 km/h respectively. Upon reaching Park S, Henry rested for 2 hours. He then headed back for Park R at an average speed of 72 km/h along the same route. Henry and Reggie met each other on their way at 2 p.m.
- How far had Henry covered when he met Reggie on the way?
- How far apart were the two parks?
(a)
Time taken by Reggie = 8 h
Time taken by Henry = 8 - 2 = 6 h
Distance covered by Henry when he met Reggie
= 6 x 72
= 432 km
(b)
Distance travelled by Reggie
= 8 x 55
= 440 km
Distance of the two parks
= (432 + 440) ÷ 2
= 872 ÷ 2
= 436 km
Answer(s): (a) 432 km; (b) 436 km