At 8 a.m., Wesley and Asher left Park D and drove towards Park E at average speeds of 85 km/h and 57 km/h respectively. Upon reaching Park E, Wesley rested for 2 hours. He then headed back for Park D at an average speed of 85 km/h along the same route. Wesley and Asher met each other on their way at 1 p.m.
- How far had Wesley covered when he met Asher on the way?
- How far apart were the two parks?
(a)
Time taken by Asher = 5 h
Time taken by Wesley = 5 - 2 = 3 h
Distance covered by Wesley when he met Asher
= 3 x 85
= 255 km
(b)
Distance travelled by Asher
= 5 x 57
= 285 km
Distance of the two parks
= (255 + 285) ÷ 2
= 540 ÷ 2
= 270 km
Answer(s): (a) 255 km; (b) 270 km