At 8 a.m., Tommy and Elijah left Park B and drove towards Park C at average speeds of 83 km/h and 61 km/h respectively. Upon reaching Park C, Tommy rested for 2 hours. He then headed back for Park B at an average speed of 83 km/h along the same route. Tommy and Elijah met each other on their way at 2 p.m.
- How far had Tommy covered when he met Elijah on the way?
- How far apart were the two parks?
(a)
Time taken by Elijah = 6 h
Time taken by Tommy = 6 - 2 = 4 h
Distance covered by Tommy when he met Elijah
= 4 x 83
= 332 km
(b)
Distance travelled by Elijah
= 6 x 61
= 366 km
Distance of the two parks
= (332 + 366) ÷ 2
= 698 ÷ 2
= 349 km
Answer(s): (a) 332 km; (b) 349 km