At 6 a.m., Elijah and Caden left Park C and drove towards Park D at average speeds of 90 km/h and 55 km/h respectively. Upon reaching Park D, Elijah rested for 2 hours. He then headed back for Park C at an average speed of 90 km/h along the same route. Elijah and Caden met each other on their way at 12 noon.
- How far had Elijah covered when he met Caden on the way?
- How far apart were the two parks?
(a)
Time taken by Caden = 6 h
Time taken by Elijah = 6 - 2 = 4 h
Distance covered by Elijah when he met Caden
= 4 x 90
= 360 km
(b)
Distance travelled by Caden
= 6 x 55
= 330 km
Distance of the two parks
= (360 + 330) ÷ 2
= 690 ÷ 2
= 345 km
Answer(s): (a) 360 km; (b) 345 km
