At 5 a.m., Fred and Lee left Park A and drove towards Park B at average speeds of 88 km/h and 62 km/h respectively. Upon reaching Park B, Fred rested for 2 hours. He then headed back for Park A at an average speed of 88 km/h along the same route. Fred and Lee met each other on their way at 1 p.m.
- How far had Fred covered when he met Lee on the way?
- How far apart were the two parks?
(a)
Time taken by Lee = 8 h
Time taken by Fred = 8 - 2 = 6 h
Distance covered by Fred when he met Lee
= 6 x 88
= 528 km
(b)
Distance travelled by Lee
= 8 x 62
= 496 km
Distance of the two parks
= (528 + 496) ÷ 2
= 1024 ÷ 2
= 512 km
Answer(s): (a) 528 km; (b) 512 km