At 6 a.m., Reggie and Will left Park C and drove towards Park D at average speeds of 80 km/h and 59 km/h respectively. Upon reaching Park D, Reggie rested for 3 hours. He then headed back for Park C at an average speed of 80 km/h along the same route. Reggie and Will met each other on their way at 2 p.m.
- How far had Reggie covered when he met Will on the way?
- How far apart were the two parks?
(a)
Time taken by Will = 8 h
Time taken by Reggie = 8 - 3 = 5 h
Distance covered by Reggie when he met Will
= 5 x 80
= 400 km
(b)
Distance travelled by Will
= 8 x 59
= 472 km
Distance of the two parks
= (400 + 472) ÷ 2
= 872 ÷ 2
= 436 km
Answer(s): (a) 400 km; (b) 436 km