At 8 a.m., Jack and Ken left Park S and drove towards Park T at average speeds of 74 km/h and 64 km/h respectively. Upon reaching Park T, Jack rested for 3 hours. He then headed back for Park S at an average speed of 74 km/h along the same route. Jack and Ken met each other on their way at 2 p.m.
- How far had Jack covered when he met Ken on the way?
- How far apart were the two parks?
(a)
Time taken by Ken = 6 h
Time taken by Jack = 6 - 3 = 3 h
Distance covered by Jack when he met Ken
= 3 x 74
= 222 km
(b)
Distance travelled by Ken
= 6 x 64
= 384 km
Distance of the two parks
= (222 + 384) ÷ 2
= 606 ÷ 2
= 303 km
Answer(s): (a) 222 km; (b) 303 km