At 5 a.m., Reggie and Charlie left Park P and drove towards Park Q at average speeds of 89 km/h and 59 km/h respectively. Upon reaching Park Q, Reggie rested for 2 hours. He then headed back for Park P at an average speed of 89 km/h along the same route. Reggie and Charlie met each other on their way at 12 noon.
- How far had Reggie covered when he met Charlie on the way?
- How far apart were the two parks?
(a)
Time taken by Charlie = 7 h
Time taken by Reggie = 7 - 2 = 5 h
Distance covered by Reggie when he met Charlie
= 5 x 89
= 445 km
(b)
Distance travelled by Charlie
= 7 x 59
= 413 km
Distance of the two parks
= (445 + 413) ÷ 2
= 858 ÷ 2
= 429 km
Answer(s): (a) 445 km; (b) 429 km
