At 7 a.m., Seth and Dylan left Park D and drove towards Park E at average speeds of 76 km/h and 53 km/h respectively. Upon reaching Park E, Seth rested for 3 hours. He then headed back for Park D at an average speed of 76 km/h along the same route. Seth and Dylan met each other on their way at 1 p.m.
- How far had Seth covered when he met Dylan on the way?
- How far apart were the two parks?
(a)
Time taken by Dylan = 6 h
Time taken by Seth = 6 - 3 = 3 h
Distance covered by Seth when he met Dylan
= 3 x 76
= 228 km
(b)
Distance travelled by Dylan
= 6 x 53
= 318 km
Distance of the two parks
= (228 + 318) ÷ 2
= 546 ÷ 2
= 273 km
Answer(s): (a) 228 km; (b) 273 km