At 6 a.m., Eric and Wesley left Park B and drove towards Park C at average speeds of 91 km/h and 56 km/h respectively. Upon reaching Park C, Eric rested for 2 hours. He then headed back for Park B at an average speed of 91 km/h along the same route. Eric and Wesley met each other on their way at 12 noon.
- How far had Eric covered when he met Wesley on the way?
- How far apart were the two parks?
(a)
Time taken by Wesley = 6 h
Time taken by Eric = 6 - 2 = 4 h
Distance covered by Eric when he met Wesley
= 4 x 91
= 364 km
(b)
Distance travelled by Wesley
= 6 x 56
= 336 km
Distance of the two parks
= (364 + 336) ÷ 2
= 700 ÷ 2
= 350 km
Answer(s): (a) 364 km; (b) 350 km