At 9 a.m., Lee and Luis left Park J and drove towards Park K at average speeds of 100 km/h and 58 km/h respectively. Upon reaching Park K, Lee rested for 2 hours. He then headed back for Park J at an average speed of 100 km/h along the same route. Lee and Luis met each other on their way at 2 p.m.
- How far had Lee covered when he met Luis on the way?
- How far apart were the two parks?
(a)
Time taken by Luis = 5 h
Time taken by Lee = 5 - 2 = 3 h
Distance covered by Lee when he met Luis
= 3 x 100
= 300 km
(b)
Distance travelled by Luis
= 5 x 58
= 290 km
Distance of the two parks
= (300 + 290) ÷ 2
= 590 ÷ 2
= 295 km
Answer(s): (a) 300 km; (b) 295 km