At 7 a.m., Bryan and Reggie left Park X and drove towards Park Y at average speeds of 98 km/h and 60 km/h respectively. Upon reaching Park Y, Bryan rested for 3 hours. He then headed back for Park X at an average speed of 98 km/h along the same route. Bryan and Reggie met each other on their way at 12 noon.
- How far had Bryan covered when he met Reggie on the way?
- How far apart were the two parks?
(a)
Time taken by Reggie = 5 h
Time taken by Bryan = 5 - 3 = 2 h
Distance covered by Bryan when he met Reggie
= 2 x 98
= 196 km
(b)
Distance travelled by Reggie
= 5 x 60
= 300 km
Distance of the two parks
= (196 + 300) ÷ 2
= 496 ÷ 2
= 248 km
Answer(s): (a) 196 km; (b) 248 km
