At 6 a.m., Gabriel and Lee left Park A and drove towards Park B at average speeds of 86 km/h and 51 km/h respectively. Upon reaching Park B, Gabriel rested for 2 hours. He then headed back for Park A at an average speed of 86 km/h along the same route. Gabriel and Lee met each other on their way at 12 noon.
- How far had Gabriel covered when he met Lee on the way?
- How far apart were the two parks?
(a)
Time taken by Lee = 6 h
Time taken by Gabriel = 6 - 2 = 4 h
Distance covered by Gabriel when he met Lee
= 4 x 86
= 344 km
(b)
Distance travelled by Lee
= 6 x 51
= 306 km
Distance of the two parks
= (344 + 306) ÷ 2
= 650 ÷ 2
= 325 km
Answer(s): (a) 344 km; (b) 325 km