At 5 a.m., Jack and Sam left Park A and drove towards Park B at average speeds of 75 km/h and 55 km/h respectively. Upon reaching Park B, Jack rested for 2 hours. He then headed back for Park A at an average speed of 75 km/h along the same route. Jack and Sam met each other on their way at 12 noon.
- How far had Jack covered when he met Sam on the way?
- How far apart were the two parks?
(a)
Time taken by Sam = 7 h
Time taken by Jack = 7 - 2 = 5 h
Distance covered by Jack when he met Sam
= 5 x 75
= 375 km
(b)
Distance travelled by Sam
= 7 x 55
= 385 km
Distance of the two parks
= (375 + 385) ÷ 2
= 760 ÷ 2
= 380 km
Answer(s): (a) 375 km; (b) 380 km