At 6 a.m., Vincent and Zeph left Park T and drove towards Park U at average speeds of 92 km/h and 53 km/h respectively. Upon reaching Park U, Vincent rested for 2 hours. He then headed back for Park T at an average speed of 92 km/h along the same route. Vincent and Zeph met each other on their way at 2 p.m.
- How far had Vincent covered when he met Zeph on the way?
- How far apart were the two parks?
(a)
Time taken by Zeph = 8 h
Time taken by Vincent = 8 - 2 = 6 h
Distance covered by Vincent when he met Zeph
= 6 x 92
= 552 km
(b)
Distance travelled by Zeph
= 8 x 53
= 424 km
Distance of the two parks
= (552 + 424) ÷ 2
= 976 ÷ 2
= 488 km
Answer(s): (a) 552 km; (b) 488 km