At 7 a.m., George and Seth left Park Y and drove towards Park Z at average speeds of 91 km/h and 60 km/h respectively. Upon reaching Park Z, George rested for 3 hours. He then headed back for Park Y at an average speed of 91 km/h along the same route. George and Seth met each other on their way at 12 noon.
- How far had George covered when he met Seth on the way?
- How far apart were the two parks?
(a)
Time taken by Seth = 5 h
Time taken by George = 5 - 3 = 2 h
Distance covered by George when he met Seth
= 2 x 91
= 182 km
(b)
Distance travelled by Seth
= 5 x 60
= 300 km
Distance of the two parks
= (182 + 300) ÷ 2
= 482 ÷ 2
= 241 km
Answer(s): (a) 182 km; (b) 241 km
