At 6 a.m., Seth and Justin left Park N and drove towards Park P at average speeds of 72 km/h and 54 km/h respectively. Upon reaching Park P, Seth rested for 2 hours. He then headed back for Park N at an average speed of 72 km/h along the same route. Seth and Justin met each other on their way at 12 noon.
- How far had Seth covered when he met Justin on the way?
- How far apart were the two parks?
(a)
Time taken by Justin = 6 h
Time taken by Seth = 6 - 2 = 4 h
Distance covered by Seth when he met Justin
= 4 x 72
= 288 km
(b)
Distance travelled by Justin
= 6 x 54
= 324 km
Distance of the two parks
= (288 + 324) ÷ 2
= 612 ÷ 2
= 306 km
Answer(s): (a) 288 km; (b) 306 km