At 6 a.m., Justin and Ken left Park T and drove towards Park U at average speeds of 97 km/h and 61 km/h respectively. Upon reaching Park U, Justin rested for 2 hours. He then headed back for Park T at an average speed of 97 km/h along the same route. Justin and Ken met each other on their way at 12 noon.
- How far had Justin covered when he met Ken on the way?
- How far apart were the two parks?
(a)
Time taken by Ken = 6 h
Time taken by Justin = 6 - 2 = 4 h
Distance covered by Justin when he met Ken
= 4 x 97
= 388 km
(b)
Distance travelled by Ken
= 6 x 61
= 366 km
Distance of the two parks
= (388 + 366) ÷ 2
= 754 ÷ 2
= 377 km
Answer(s): (a) 388 km; (b) 377 km