At 6 a.m., Reggie and Jack left Park W and drove towards Park X at average speeds of 90 km/h and 60 km/h respectively. Upon reaching Park X, Reggie rested for 2 hours. He then headed back for Park W at an average speed of 90 km/h along the same route. Reggie and Jack met each other on their way at 12 noon.
- How far had Reggie covered when he met Jack on the way?
- How far apart were the two parks?
(a)
Time taken by Jack = 6 h
Time taken by Reggie = 6 - 2 = 4 h
Distance covered by Reggie when he met Jack
= 4 x 90
= 360 km
(b)
Distance travelled by Jack
= 6 x 60
= 360 km
Distance of the two parks
= (360 + 360) ÷ 2
= 720 ÷ 2
= 360 km
Answer(s): (a) 360 km; (b) 360 km