At 5 a.m., Xavier and Tim left Park T and drove towards Park U at average speeds of 73 km/h and 64 km/h respectively. Upon reaching Park U, Xavier rested for 3 hours. He then headed back for Park T at an average speed of 73 km/h along the same route. Xavier and Tim met each other on their way at 12 noon.
- How far had Xavier covered when he met Tim on the way?
- How far apart were the two parks?
(a)
Time taken by Tim = 7 h
Time taken by Xavier = 7 - 3 = 4 h
Distance covered by Xavier when he met Tim
= 4 x 73
= 292 km
(b)
Distance travelled by Tim
= 7 x 64
= 448 km
Distance of the two parks
= (292 + 448) ÷ 2
= 740 ÷ 2
= 370 km
Answer(s): (a) 292 km; (b) 370 km