At 5 a.m., Albert and Vincent left Park E and drove towards Park F at average speeds of 98 km/h and 60 km/h respectively. Upon reaching Park F, Albert rested for 2 hours. He then headed back for Park E at an average speed of 98 km/h along the same route. Albert and Vincent met each other on their way at 12 noon.
- How far had Albert covered when he met Vincent on the way?
- How far apart were the two parks?
(a)
Time taken by Vincent = 7 h
Time taken by Albert = 7 - 2 = 5 h
Distance covered by Albert when he met Vincent
= 5 x 98
= 490 km
(b)
Distance travelled by Vincent
= 7 x 60
= 420 km
Distance of the two parks
= (490 + 420) ÷ 2
= 910 ÷ 2
= 455 km
Answer(s): (a) 490 km; (b) 455 km
