At 5 a.m., Jenson and Reggie left Park D and drove towards Park E at average speeds of 84 km/h and 60 km/h respectively. Upon reaching Park E, Jenson rested for 3 hours. He then headed back for Park D at an average speed of 84 km/h along the same route. Jenson and Reggie met each other on their way at 2 p.m.
- How far had Jenson covered when he met Reggie on the way?
- How far apart were the two parks?
(a)
Time taken by Reggie = 9 h
Time taken by Jenson = 9 - 3 = 6 h
Distance covered by Jenson when he met Reggie
= 6 x 84
= 504 km
(b)
Distance travelled by Reggie
= 9 x 60
= 540 km
Distance of the two parks
= (504 + 540) ÷ 2
= 1044 ÷ 2
= 522 km
Answer(s): (a) 504 km; (b) 522 km