At 7 a.m., Luke and Xavier left Park S and drove towards Park T at average speeds of 88 km/h and 62 km/h respectively. Upon reaching Park T, Luke rested for 3 hours. He then headed back for Park S at an average speed of 88 km/h along the same route. Luke and Xavier met each other on their way at 12 noon.
- How far had Luke covered when he met Xavier on the way?
- How far apart were the two parks?
(a)
Time taken by Xavier = 5 h
Time taken by Luke = 5 - 3 = 2 h
Distance covered by Luke when he met Xavier
= 2 x 88
= 176 km
(b)
Distance travelled by Xavier
= 5 x 62
= 310 km
Distance of the two parks
= (176 + 310) ÷ 2
= 486 ÷ 2
= 243 km
Answer(s): (a) 176 km; (b) 243 km