At 6 a.m., Gabriel and Lee left Park H and drove towards Park J at average speeds of 98 km/h and 54 km/h respectively. Upon reaching Park J, Gabriel rested for 2 hours. He then headed back for Park H at an average speed of 98 km/h along the same route. Gabriel and Lee met each other on their way at 12 noon.
- How far had Gabriel covered when he met Lee on the way?
- How far apart were the two parks?
(a)
Time taken by Lee = 6 h
Time taken by Gabriel = 6 - 2 = 4 h
Distance covered by Gabriel when he met Lee
= 4 x 98
= 392 km
(b)
Distance travelled by Lee
= 6 x 54
= 324 km
Distance of the two parks
= (392 + 324) ÷ 2
= 716 ÷ 2
= 358 km
Answer(s): (a) 392 km; (b) 358 km