At 9 a.m., Seth and Jenson left Park X and drove towards Park Y at average speeds of 79 km/h and 64 km/h respectively. Upon reaching Park Y, Seth rested for 2 hours. He then headed back for Park X at an average speed of 79 km/h along the same route. Seth and Jenson met each other on their way at 1 p.m.
- How far had Seth covered when he met Jenson on the way?
- How far apart were the two parks?
(a)
Time taken by Jenson = 4 h
Time taken by Seth = 4 - 2 = 2 h
Distance covered by Seth when he met Jenson
= 2 x 79
= 158 km
(b)
Distance travelled by Jenson
= 4 x 64
= 256 km
Distance of the two parks
= (158 + 256) ÷ 2
= 414 ÷ 2
= 207 km
Answer(s): (a) 158 km; (b) 207 km