At 5 a.m., Tommy and Albert left Park R and drove towards Park S at average speeds of 99 km/h and 50 km/h respectively. Upon reaching Park S, Tommy rested for 3 hours. He then headed back for Park R at an average speed of 99 km/h along the same route. Tommy and Albert met each other on their way at 12 noon.
- How far had Tommy covered when he met Albert on the way?
- How far apart were the two parks?
(a)
Time taken by Albert = 7 h
Time taken by Tommy = 7 - 3 = 4 h
Distance covered by Tommy when he met Albert
= 4 x 99
= 396 km
(b)
Distance travelled by Albert
= 7 x 50
= 350 km
Distance of the two parks
= (396 + 350) ÷ 2
= 746 ÷ 2
= 373 km
Answer(s): (a) 396 km; (b) 373 km