At 5 a.m., Luis and Nick left Park E and drove towards Park F at average speeds of 100 km/h and 56 km/h respectively. Upon reaching Park F, Luis rested for 3 hours. He then headed back for Park E at an average speed of 100 km/h along the same route. Luis and Nick met each other on their way at 12 noon.
- How far had Luis covered when he met Nick on the way?
- How far apart were the two parks?
(a)
Time taken by Nick = 7 h
Time taken by Luis = 7 - 3 = 4 h
Distance covered by Luis when he met Nick
= 4 x 100
= 400 km
(b)
Distance travelled by Nick
= 7 x 56
= 392 km
Distance of the two parks
= (400 + 392) ÷ 2
= 792 ÷ 2
= 396 km
Answer(s): (a) 400 km; (b) 396 km
