At 5 a.m., Fred and Tommy left Park Y and drove towards Park Z at average speeds of 92 km/h and 64 km/h respectively. Upon reaching Park Z, Fred rested for 2 hours. He then headed back for Park Y at an average speed of 92 km/h along the same route. Fred and Tommy met each other on their way at 12 noon.
- How far had Fred covered when he met Tommy on the way?
- How far apart were the two parks?
(a)
Time taken by Tommy = 7 h
Time taken by Fred = 7 - 2 = 5 h
Distance covered by Fred when he met Tommy
= 5 x 92
= 460 km
(b)
Distance travelled by Tommy
= 7 x 64
= 448 km
Distance of the two parks
= (460 + 448) ÷ 2
= 908 ÷ 2
= 454 km
Answer(s): (a) 460 km; (b) 454 km
